package org.interview.test;
import java.util.Scanner;
/**
* Above code locate first instance of element to found, you can modify it for multiple
* occurrence of same element and count how many times it occur in the list.
* Similarly you can find if an alphabet is present in a string.
*
*/
public class LinearSearch {
public static void main (String [] args) throws Exception {
int c, n, search, array[];
Scanner in = new Scanner(System.in);
System.out.println("Enter number of elements");
n = in.nextInt();
array = new int[n];
System.out.println("Enter " + n + " integers");
for (c = 0; c < n; c++)
array[c] = in.nextInt();
System.out.println("Enter value to find");
search = in.nextInt();
for (c = 0; c < n; c++)
{
if (array[c] == search) /* Searching element is present */
{
System.out.println(search + " is present at location " + (c + 1) + ".");
break;
}
}
if (c == n) /* Searching element is absent */
System.out.println(search + " is not present in array.");
}
}
import java.util.Scanner;
/**
* Above code locate first instance of element to found, you can modify it for multiple
* occurrence of same element and count how many times it occur in the list.
* Similarly you can find if an alphabet is present in a string.
*
*/
public class LinearSearch {
public static void main (String [] args) throws Exception {
int c, n, search, array[];
Scanner in = new Scanner(System.in);
System.out.println("Enter number of elements");
n = in.nextInt();
array = new int[n];
System.out.println("Enter " + n + " integers");
for (c = 0; c < n; c++)
array[c] = in.nextInt();
System.out.println("Enter value to find");
search = in.nextInt();
for (c = 0; c < n; c++)
{
if (array[c] == search) /* Searching element is present */
{
System.out.println(search + " is present at location " + (c + 1) + ".");
break;
}
}
if (c == n) /* Searching element is absent */
System.out.println(search + " is not present in array.");
}
}
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